25=a(3.3^2)+18.98

Solution for 25=a(3.3^2)+18.98 equation:

25=a(3.3^2)+18.98

We move all terms to the left:

25-(a(3.3^2)+18.98)=0


We calculate terms in parentheses: -(a(3.3^2)+18.98), so:

a(3.3^2)+18.98

We multiply parentheses

3a^2+18.98

Back to the equation:

-(3a^2+18.98)


We get rid of parentheses

-3a^2-18.98+25=0

We add all the numbers together, and all the variables

-3a^2+6.02=0

a = -3; b = 0; c = +6.02;
Δ = b2-4ac
Δ = 02-4·(-3)·6.02
Δ = 72.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{72.24}}{2*-3}=\frac{0-\sqrt{72.24}}{-6}
=-\frac{\sqrt{}}{-6}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{72.24}}{2*-3}=\frac{0+\sqrt{72.24}}{-6}
=\frac{\sqrt{}}{-6}
$